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PAT 1077. Kuchiguse (20)

http://www.patest.cn/contests/pat-a-practise/1077
The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker’s personality. Such a preference is called “Kuchiguse” and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle “nyan~” is often used as a stereotype for characters with a cat-like personality:
 

  • Itai nyan~ (It hurts, nyan~)
  • Ninjin wa iyada nyan~ (I hate carrots, nyan~)

 
Now given a few lines spoken by the same character, can you find her Kuchiguse?
 
这个题目就是到着找最长相同子串,没啥难度,用char数组操作很方便,直接给代码

#include <iostream>
#include <string.h>
using namespace std;
bool tryMoveForward(int N, char** sentences, int* posPtr, bool &contFlag)
{
	//尝试当前位置的字符是否相同
	char chr = sentences[0][posPtr[0]];
	bool flag = true;
	int i = 0;
	while(i < N)
	{
		if (sentences[i][posPtr[i]] != chr)
		{
			flag = false;
			break;
		}
		i++;
	}
	if (flag)
	{
		//Move forward
		for (i = 0; i < N; i++)
		{
			posPtr[i] --;
			if (posPtr[i] <0)
				contFlag = false;
		}
	}
	return flag;
}
int main()
{
	int N;
	cin >> N;
	char **sentences = new char*[N]; //存储句子
	int* posPtr = new int[N];	//当前位置指针
	//int maxSuffixStartPos = 0; //最长子串起始位置(距离最后一个字符)
	cin.ignore(1);
	for (int i = 0; i < N; i++)
	{
		sentences[i] = new char[257];
		//cin >> sentences[i];
		cin.getline(sentences[i], 257);
		posPtr[i] = strlen(sentences[i]) - 1;
	}
	bool contFlag = true;
	while (contFlag)
	{
		bool movFlag = tryMoveForward(N, sentences, posPtr, contFlag);
		contFlag &= movFlag;
	}
	//读取最长字串
	int longSufPos = posPtr[0];
	if (longSufPos == strlen(sentences[0]) - 1)
		cout << "nai";
	else
	{
		char* result = sentences[0] + longSufPos + 1;
		cout << result;
	}
	return 0;
}

 

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